Can u tell me the plan to learn php?

Please code it

laravel_hindi

How to use eval() safe
How can it be dangerous

PHP developer DM me for paid small work

Can u tell me the plan to learn php?

Php project hai kya kisi ke pass

We are looking out for an experienced Front-end developer that has worked with reactjs to help towards a development of a couple of backend dashboards built up in html bootstrap and reactjs your task is mainly to handle all the api development and making all designs ready for Front-end well documented up for backend development designer must be a full time freelancer and must be very fast at getting work done with Front-end

Guys I have query
I have three records in table
Every records have multiple data into another table but my issue is I want show the data serial wise like example
A, B, C
This is three record
A1, A2
B1, B2
C1, C2
This record link to A, B, C

Hi friends login biometric attendance system in php Do I need any one help

Please help the code does not work…

<?php
if (isset($_POST[‘upload’])){
$book= $_POST[‘book’];
$author=$_POST[‘author’];
$about=$_POST[‘about’];
$story=$_POST[‘story’];
$file=$_FILES[‘file’];
$filename=$_file[‘name’];
$fileerror=$files[‘error’];
$filetmp=$file[‘tmp_name’];
$fileext=explode(‘.’,$filename);
$filecheck=strtolower(end($fileout));
$fileextstored= array(‘png’,’jpg’,’jpeg’);
if(in_array($filecheck,$fileextstored)){
$destinationfile=”images/”.$filename;
move_uploaded_file($filetmp,$destinationfile);
$q=”INSERT INTO books(image, heading, author, about, story) VALUES (‘$destinationfile’,’$book’,’$author’,’$about’,’$story’)”;
$query= mysqli_query($conn,$q);

if (move_uploaded_file($_FILES[‘image’][‘tmp_name’], $target)) {
$msg = “Image uploaded successfully”;
}else{
$msg = “Failed to upload image”;
}
}
}

?>

What’s the issue

<?php include “config.php”;

image uploading

the code does not work

<?php include “config.php”; if (isset($_POST[‘upload’])){
$book= $_POST[‘book’];
$author=$_POST[‘author’];
$about=$_POST[‘about’];
$story=$_POST[‘story’];
$file=$_FILES[‘file’];
$filename=$_file[‘name’];
$fileerror=$files[‘error’];
$filetmp=$file[‘tmp_name’];
$fileext=explode(‘.’,$filename);
$filecheck=strtolower(end($fileout));
$fileextstored= array(‘png’,’jpg’,’jpeg’);
if(in_array($filecheck,$fileextstored)){
$destinationfile=”images/”.$filename;
move_uploaded_file($filetmp,$destinationfile);
$q=”INSERT INTO books(image, heading, author, about, story) VALUES (‘$destinationfile’,’$book’,’$author’,’$about’,’$story’)”;
$query= mysqli_query($conn,$q);

if (move_uploaded_file($_FILES[‘image’][‘tmp_name’], $target)) {
$msg = “Image uploaded successfully”;
}else{
$msg = “Failed to upload image”;
}
}
}

?>

<form method=”POST” action=”post.php” enctype=”multipart/form-data”>

<input type=”hidden” name=”size” value=”1000000″>

<label for=”formFileSm” class=”form-label”> Upload book cover</label>

<input class=”form-control form-control-sm” id=”formFileSm” type=”file” name=”image”><br>

<textarea class=”form-control” placeholder=”Book Name” id=”floatingTextarea” name=”book”></textarea><br>

<textarea class=”form-control” placeholder=”Author name” id=”floatingTextarea” name=”author”></textarea><br>

<textarea class=”form-control” placeholder=”About the book” id=”floatingTextarea” name=”about”></textarea><br>

<textarea id=”editor” name=”story” > Write your book.. </textarea> <br><br>

<button class=”submitbutton” type=”submit” name=”upload”>Submit</button>
</form>

What is expected output

What it actually output

image and text save to database

what is the error dude, cant you tell in one

Undefined index

line??

send line 93

$file=$_FILES[‘file’];

use image inside $_FILE

you provided name as image and using file as name

and write code with proper syntax, somewhere using file and somewhere FILE, both are different, learn php then do things

How to learning php

+1

learn English first