Guy any idea of retrieve Mysql Data as Json from the data type of JSON?

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R 2021-08-09 12:55:19
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Does anyone know how to avoid this type of names match while submitting the form using regular expressions

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Anurag34803 2021-08-10 10:38:59
WaseemBittu 2021-08-10 10:20:23
Does anyone know how to avoid this type of names match while submitting the form using regular expressions

First Name : aaaa
Last Name : bbb

how to solve this using regular expressions please help me…

Use contain property in php

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Use contain property in php

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WaseemBittu 2021-08-10 10:20:23
Does anyone know how to avoid this type of names match while submitting the form using regular expressions

First Name : aaaa
Last Name : bbb

how to solve this using regular expressions please help me…

if (preg_match(‘/(.)\1{4}/’, $str) || preg_match(‘/(.)\1{3}/’, $str)){

johnmelodyme 2021-08-10 15:03:45
Guy any idea of retrieve Mysql Data as Json from the data type of JSON ?

sql
CREATE TABLE `A`.`B`(`C` ID, `D` JSON NOT NULL):

sql
INSERT INTO `A`.`B`(`D`) VALUES (JSON_OBJECT(‘something’, JSON_ARRAY(‘whatever_one’, ‘whatever_two’, ‘whatever_three’)));

Expecting:

json
{“something”, [{“whatever_one”, “whatever_two”, “whatever_two”}]}

Any Idea by using php?

I tried
sql
SELECT * FROM `A`.`B`;

I wasn’t print out the JSON colum as JSON.

aljberbz 2021-08-10 15:07:48
codeslide-40711.jpg

aljberbz 2021-08-10 15:07:49
codeslide-40712.jpg

aljberbz 2021-08-10 15:08:04
Hello everyone, Can you help me to fix this error? I cant get the code exactly
aljberbz 2021-08-10 15:08:37
Line 2 3 and 4
aljberbz 2021-08-10 15:11:01
3 4 5*
johnmelodyme 2021-08-10 15:56:08
johnmelodyme 2021-08-10 15:03:45
Guy any idea of retrieve Mysql Data as Json from the data type of JSON ?

sql
CREATE TABLE `A`.`B`(`C` ID, `D` JSON NOT NULL):

sql
INSERT INTO `A`.`B`(`D`) VALUES (JSON_OBJECT(‘something’, JSON_ARRAY(‘whatever_one’, ‘whatever_two’, ‘whatever_three’)));

Expecting:

json
{“something”, [{“whatever_one”, “whatever_two”, “whatever_two”}]}

Any Idea by using php?

I tried
sql
SELECT * FROM `A`.`B`;

I wasn’t print out the JSON colum as JSON.

It’s OK, I found out a solution.

mysql
SELECT JSON_EXTRACT(
`{NAME_OF_COLUMN}`,
‘$.{NAME_OF_JSON_OBJECT}’
)
FROM
`{NAME_OF_DATABASE}`.`{NAME_OF_TABLE}`

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